Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
Answer:
1. R
2. Match the year with the price. For example, 2006 should have a line directly on 15.
3. A (The first number on each row is the second number multiplied by 4)
4. C
5. A
MAKE SURE TO DOUBLE-CHECK JUST IN CASE!
Answer:
The number of pair of gym shoes does Mr. king has is 27 pairs .
Step-by-step explanation:
Given as :
Total number of pairs of shoes does king has = 36 pairs
The number of gym shoes =
of the total pairs of shoes
Let The number of pair of gym shoes = n
<u>According to question</u>
The number of gym shoes =
× the total pairs of shoes
Or, n =
× 36
i.e n = 
Or, n = 3 × 9
∴ n = 27
So, The number of pair of gym shoes = n = 27 pairs
Hence, The number of pair of gym shoes does Mr. king has is 27 pairs . Answer
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
C
Step-by-step explanation: