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2 years ago

Compared to others, which one of the following is not robust to outliers? a) Mean b) Median c) Mode d) 50th percentile

Mathematics

1 answer:

tatyana61 [14]2 years ago

3 0

Answer:

The mean.

Step-by-step explanation:

The mean is not robust.

The presence of an outlier greatly affects the value of a mean.

An example will illustrate this.

Find the mean of the numbers 2 3 5 6 34.

34 is an outlier. The mean = (2+3+5+6+34) / 5 = 10.

Now if we replace the outlier with a number closer to the others:

Say we have 2 3 5 6 8 :

The mean = (2+3+5+6+8) / 5 = 4.8 which is a much truer measure of centrality than 10.

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Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°

Lerok [7]

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is $sin\: x = cos 19^{\circ}$ , where 0°< x < 90°?

Solving:

$sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}$

So, we get x = 71°

Option B is correct answer.

5 0

2 years ago

How would I do this problem?

kenny6666 [7]

If it's a geometric sequence then:

$a_1=27;\ a_2=27\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{27}{36}=\dfrac{3}{4}=0.75\\\\a_{n+1}=a_nr\\\\a_3=27\cdot0.75=20.25\ CORRECT$

We calculate the fourth and fifth term of the sequence:

$a_4=a_3r\to a_4=20.25\cdot0.75=15.1875\\\\a_5=a_4r\to a_5=15.1875\cdot0.75=11.390625$

Answer:

In year 4 15.1875 animals.

In year 5 11.390625 animals.

7 0

2 years ago

Which property is used in the following expression? 2 x 3 = 3 x 2

posledela

Answer:

because i learned it in class 2 years ago

Step-by-step explanation:

b. Associative Property of Multiplication

7 0

2 years ago

Read 2 more answers

When solving an equation in the form ax^2=c by taking square roots, how many solutions will there be?

sergij07 [2.7K]

I think there would be two soulutions. ax^2 and c^2. Hope it's right. sorry if it is not. But hope it is and hope it helps.

7 0

2 years ago

What is the most precise classification of the quadrilateral formed by connecting in order the midpoints of the figure below? Sh

AlekseyPX

Answer:

Rhombus

Step-by-step explanation:

The given trapezoid has vertices at M(-4,0), J(-2,4), K(2,4), and L(4,0).

Use the midpoint formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

To obtain the midpoint of MJ:

$A=(\frac{-4+-2}{2},\frac{0+4}{2})=(-3,2)$

Similarly, the midpoint of of JK is B=(0,4), the midpoint of KL is C=(3,2), and the midpoint of LM is D=(0,0).

Now use the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

To find the slope of AB = $\frac{4-2}{0--3}=\frac{2}{3}$

The slope of BC = $\frac{2-4}{3-0} =-\frac{2}{3}$

The slope of CD= $\frac{0-2}{0-3}=\frac{2}{3}$

The slope of AD= $\frac{0-2}{0--3}=-\frac{2}{3}$

We can see that the slope of the opposites sides are parallel, CD is parallel to AB and AD is parallel to BC.

The product of the slopes of the adjacent sides is not -1.

Hence the shape formed by connecting the midpoint of the isosceles trapezoid is a parallelogram.

Obviously the side lengths are equal since we connected all midpoints.

The parallelogram is a rhombus.

7 0

2 years ago