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MArishka [77]
3 years ago
14

I need help with this question from my daughters 1st grade math class. I believe the answer should be 12 but the teacher says th

e answer should be 6. How is the answer 6?
Mackenzie picks some apples.
She eats 3 apples.
Now she has 9 apples.
How many apples did Mackenzie pick to start?
A. 3 apples
B. 6 apples
C. 9 apples
D. 12 apples
Mathematics
2 answers:
Colt1911 [192]3 years ago
5 0

Answer: Option D 12 apples

Step-by-step explanation:

SOOOO

She ate 3 apples and after that, she left with the 9 apples

They asked how many did Mackenzie pick.

SO its past tense

we have to add 3 apples that she just ate

so 9+3= 12 apples

I think your teacher is wrong because I think your teacher thought that she had 9 apples actually she has 9 apples after she just ate. So if it was before she has eaten the apples then it would be 6

Tell the teacher that she/he is wrong and give this explanation  

I hope this helps you and your teacher

padilas [110]3 years ago
3 0

Answer:

d.12

Step-by-step explanation:

its saying she ate 3 an now has 9. so you really add 3 to 9 an your answer is 12. in other words x=9+3 for your level of math. i'll be glad to help her with her home work for now if you would like me to.

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bekas [8.4K]

(4.1 \times  {10}^{ - 2}) - (2.6 \times  {10}^{ - 3}) =  \\

(4.1 \times  {10}^{ - 2}) - (0.26 \times  {10}^{ - 2}) =  \\

Factoring \:  \:  {10}^{ - 2}

(4.1 - 0.26) \times  {10}^{ - 2}  =

3.84 \times  {10}^{ - 2}

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3 years ago
After eliminating radicals, what quadratic equation can you solve to find the potential solutions of ..
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Answer:

Step-by-step explanation:

4 0
4 years ago
The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US
alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\

 Calculating the sample size:

\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2

      = (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23

In point b:

\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\

      = (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62

In point c:

\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\

      = (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139    

4 0
3 years ago
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Nataly_w [17]

Answer:  try C

Step-by-step explanation:

5 0
3 years ago
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