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jeyben [28]
3 years ago
13

Which angles are co-terminal with 3π/2 ?

Mathematics
1 answer:
irina1246 [14]3 years ago
7 0
One is 3pi/2 - 2pi  = -pi/2

also -7pi/2
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Write each of the following expressions without using the absolute value sign. |x−4| if x>4
RSB [31]

Answer:

x-4

Step-by-step explanation:

|x−4|  if x>4

That means x-4 is always positive since x> 4

x-4

6 0
3 years ago
4. John wants to cover a box entirely with silver paper. How many square centimetres
masya89 [10]

Answer:

4.

l=22cm

b:16cm

h:10cm

surface area =2(lb+bh+lh)=2(22*16+16*10+22*10)

=1464cm²

5.

a=2.5dm

area cubical soda cracker box=6a²=6*2.5²=37.5dm²

6.

r=1.5dm

area of ball=4πr²=4π×1.5²=28.27dm² per ball

for 10 bal =28.27×10=282.6dm²

8 0
3 years ago
Please help!!
Marysya12 [62]

The LCD of 3 and 4 is 12. To make 4 into 12, we multiply it by three, so 3 would also have to be multiply by 3, turning 3/4 into 9/12.

The same thing applies to 1/3, only it needs to be multiplied by 4. So it would become 4/12

9/12 - 4/12 = 5/12

4 0
3 years ago
Read 2 more answers
The graph of the function f(x) = -(x+3)(x - 1) is shown below. What is true about the domain and range of the function? у The do
Nataly_w [17]

Answer:

The domain will be all real numbers, range will be all real numbers below -3

Step-by-step explanation:

its quadratic so it goes forever left and right. but the vertex has a y value of -3. It is a negative sloped graph, so anything below that is in the range

5 0
3 years ago
If z=3−5i, find |z|.
geniusboy [140]

Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane.  In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number.  Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point.  Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5.  To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem.  Therefore:

|z|=\sqrt{(3)^2+(-5)^2} and

|z|=\sqrt{9+25} and

|z|=\sqrt{34}

5 0
3 years ago
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