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2 years ago

11

What is the solution to the system of equations

1 answer:

snow_tiger [21]2 years ago

6 0

Answer:

For the equations -x-2y=-6 and -3x+2y=6, the solution is x=0 and x=3. You can also write it as (0,3). For the equations 3x+8y=-4 and 2x-4y=16, the solution is x=4, and x=-2. You can also write it as (4,-2)

Step-by-step explanation:

Solve the systems of equations

You might be interested in

A roped-off area of width x is created around a 30- by 10-foot rectangular museum display of Native American artifacts. The comb

Monica [59]

Answer: $4x^{2}+80x-500=0$

Step-by-step explanation:

1. You know that:

- The roped-off area whose width is represented with <em>x,</em> it is created around a rectangular museum.

- The dimensions of the rectangular museum are: 30 ft by 10 ft.

- The combined area of the display and the roped-off area is 800 ft².

2. The area of the rectangular museum can be calculated with:

$A=l*w$

Where $l$ is the lenght and $w$ is the width.

You have that the lenght and the width in feet are:

$l=30\\w=10$

3. Let's call $x$ the width of the roped-off area. Then, the combined area is:

$A_c=l_c*w_c$

Where

$A_c=800$

$l_c=l+x+x=30+2x$

$w_c=w+x+x=10+2x$

4. Substitute values and simplify. Then:

$800=(30+2x)(10+2x)$

$800=300+60x+20x+4x^{2}\\4x^{2}+80x-500=0$

5 0

3 years ago

2а + 20 = -3а - 5 pls help

sammy [17]

Answer: A= -5

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0

2 years ago

Which of the following numbers are greater than or equal to 4/7

Alexandra [31]

B and C mark brainly!

8 0

2 years ago

What is 3/4 as a percentage

luda_lava [24]

Answer:

75%

Step-by-step explanation:

A percent is a value out of 100.

Change the fraction $\frac{3}{4}$ to an equivalent fraction with the denominator equal to 100.

$\frac{3}{4}$ × $\frac{25}{25}$ = $\frac{75}{100}$

This fraction represents a percent.

$\frac{75}{100}$ = 75%

5 0

2 years ago