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3 years ago

Figure consists of a tangent and a secant to the circle. Solve for x

Mathematics

1 answer:

ryzh [129]3 years ago

3 0

For every y go for x which is 1,1 and can go forever

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When a triangular prism is intersected by a plane parallel to the bases, what is

IgorC [24]

Answer:

C: triangle

Step-by-step explanation:

the cross section is a triangle that is smaller than the base triangle.

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2 years ago

Anwar is thinking of a number. He gives three clues about his number: It is an odd number; The number is less than -12; and The

tigry1 [53]

Answer:

-13

Step-by-step explanation:

it must be either -11 or -13. -13 is less than -12.

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2 years ago

Answer choices are

3241004551 [841]

if asking for hours to miles (as it looks like in this case, x to y) it would be 1/53

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3 years ago

Find the area of the triangle

BARSIC [14]

Answer:

The Area of Δ ABC = 219.13

Step-by-step explanation:

The hard part about this problem is finding the area without the height

The formula to do this is Area = $\sqrt{S(S-A)(S-B)(S-C)}$

A, B, C represent the sides

S represents $\frac{1}{2}$ (A + B + C)

In this equation, we will make the base be A, and the other two sides will be B and C

Sides B and C are the same length because they meet at a 90° angle

Lets plug the numbers into the variables

A = 28

B= 21

C= 21

Remember: S represents $\frac{1}{2}$ (A + B + C)

S = $\frac{1}{2}$ (28 + 21 + 21)

S = $\frac{1}{2}$ (70)

S = 35

Lets plug the numbers into the Area Formula now!

Area = $\sqrt{35(35 - 28)(35 - 21)(35 - 21)}$

According to the order of operations, we need to do the calculations in parentheses first

35 - 28 = 7

35 - 21 = 14

14 x 14 x 7 = 1372

1372 x 35 = 48020

$\sqrt{48020}$ = 219.13

The Area of Δ ABC = 219.13

3 0

3 years ago

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .