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nadezda [96]
2 years ago
11

Observe the graph below. The scale factor used to dilate ABC was...

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
7 0

Answer:

3

Step-by-step explanation:

AB = 1 unit

A'B' = 3 units

The scale of dilation = A'B'/AB

Therefore:

scale of dilation = 3 units / 1 unit = 3

This means that ABC was dilated or enlarged in size by multiplying every of its segment by 3. In essence, A'B'C' is 3 times the size of ABC.

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Help needed.<br> here is some text
slamgirl [31]
Checking the graph:-  when x = 1 y = 0  so it cant be y = x^4

y = log4 x
is the same as

x = 4^y 

Checking the graph,  when x = 4, y = 1
Plugging these into the above 4 = 4^1 = 4

So the correct choice is first one 

8 0
3 years ago
Solve h = −16t2 + 36t + 4.
kvasek [131]
I can do each of the things I asked above.
So, let's change this into vertex form:
h=-16t^2+36t+4
h=(-16t^2+36t)+4
h=-16(t^2-2.25t)+4
h=-16(t^2-2.25t+1.27-1.27)+4
h=-16(t^2-2.25t+1.27)+20.32+4
h=-16(t-1.125)^2+24.32
The vertex is at (1.125,24.32)
<span>Answers may vary due to rounding

</span>Factored Form:
h = -16t^2 + 36t + 4
h = -4\left(4t^2-9t-1\right)

Quadratic Formula:
x =  \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}
<span>h = -16t^2 + 36t + 4
</span>a = -16 b = 36 c = 4
h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}
h = \frac{-36 +/- \sqrt{1552}}{-32}
h = ≈-0.11
h = ≈2.36

5 0
2 years ago
Help me please.No spammmers.
egoroff_w [7]

Answer:

C

Step-by-step explanation:

cot =cos/sin =a/b

cos=a/b*sin

(sin-cos)/(sin+cos) =(sin-sin*a/b)(sin+sin*a/b)

=(1-a/b)/(a+a/b)

=(b-a)/(a+b)

5 0
3 years ago
What is the simplified expression for 3^3 . 3^3/3^4
jeka57 [31]
The answer is 9 or 3^2.
6 0
3 years ago
the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference
adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: a=2

Sum of first 15 terms: S_{15}=292.5

The formula of sum of first n terms of an AP is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Where, a is first term and d is common difference.

Putting S_{15}=292.5, n=15 and a=2 in the above formula, we get

292.5=\dfrac{15}{2}[2(2)+(15-1)d]

292.5=\dfrac{15}{2}[4+14d]

292.5=15[2+7d]

Divide both sides by 15.

\dfrac{292.5}{15}=2+7d

19.5=2+7d

19.5-2=7d

17.5=7d

Dividing both sides by 7, we get

\dfrac{17.5}{7}=d

2.5=d

Therefore, the common difference is 2.5.

8 0
3 years ago
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