Answer:
308[cos(45) + isin(45)]
Step-by-step explanation:
z1×z2:
Modulus: r1 × r2
= 7×44 = 308
Argument: theta1 + theta2
= -70 + 115 = 45
z1z2 = 308[cos(45) + isin(45)]
Or
z1z2 = 154sqrt(2) + (i)154sqrt(2)
sqrt: square root
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
The answer to your question is 113.04 in²
Step-by-step explanation:
To solve this problem substitute the values in the formula and simplify.
Data
Area = ?
radius = 6 in
π = 3.14
Formula
Area = π x r²
Substitution
Area = (3.14) x (6)²
Simplification
Area = 3.14 x 36
Result
Area = 113.04 in²
Answer:
8. yes, ASA
9. yes, SAS
10. yes, AAS
11. no
12. no
13. yes, SSS
Step-by-step explanation:
