All categories

2 years ago

An actor was paid $2.1 x 10^6 (this an exponent) to star in a movie. If the

Mathematics

1 answer:

Zigmanuir [339]2 years ago

8 0

Answer:

Step-by-step explanation:

one hour and 45 min=60+45=105 minutes

2.1x 10^6=210x 10^4 , i multiplied 2.1 by 100

210 x 10^4/105=2 x10^4=20,000/min

You might be interested in

Algebra help please I have to get it done .

Finger [1]

Its Letter A see photo for solution

3 0

3 years ago

[50 Points each!!!] and Brainliest!

beks73 [17]

Answer:

The difference between iPhone 11 and Spinal cord repairence is 99,300$.

Step-by-step explanation:

To be honest, this is a really weird question. But a spinal cord injury can cost up to 100,000$ a year. And an iPhone 11 cost around 700$. It really just depends on what repairence the person got, but if I am wrong then I hope you the best with your question lol. And since Alex didnt break his phone, you wouldnt count the repairs for the iPhone 11.

8 0

2 years ago

Cube and cube roots 27000

boyakko [2]

Answer:

lcm for cuberoot

2*2*2*5*5*5*3*3*3

for cuberoot we will make pairs of common three numbers and write them one time

2*5*3

check 30*30*30=27000

cube

multiply 27000 three times with itself

19683000000000.0 is the answer

6 0

2 years ago

Read 2 more answers

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

Can someone help me please

soldier1979 [14.2K]

Step-by-step explanation:

c >= 2

that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.

c < 2

that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.

c < 3

that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.

3 < c

that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.

-8 < c

that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.

5 0

2 years ago