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blagie [28]
3 years ago
15

Need this asap please help!​

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Its A

Step-by-step explanation                                                                                         The dolphin swam 3 feet more which is -7

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Solve triangle ABC with m
Irina18 [472]
Yeah I’ll get right on that.
3 0
3 years ago
Find the slope of the line that passes through (23, -30) and (-7, 18).
babymother [125]

Answer:

slope = - \frac{8}{5}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (23, - 30) and (x₂, y₂ ) = (- 7, 18)

m = \frac{18-(-30)}{-7-23} = \frac{18+30}{-30} = \frac{48}{-30} = - \frac{8}{5}

6 0
3 years ago
How many four-character passwords can be formed using the characters A, B, C, 1, 2 if the characters can be repeated
olga55 [171]
<h3>Answer: 625</h3>

Work Shown:

The set {A,B,C,1,2} has five items. There are four slots to fill.

So we have 5^4 = 5*5*5*5 = 625 different possible passwords where the characters can be repeated.

7 0
3 years ago
Find the inverse of the following matrix without using a calculator 1-1 2 -3 2 1 0 4 - 25
Artist 52 [7]

Answer:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

Step-by-step explanation:

You can solve this problem by using the Gauss-Jordan method.

You have the original matrix and then the Identity matrix.

So:

Original              Identity

1 -1 2                    1 0 0

-3 2 1                   0 1 0

0 4 -25                0 0 1

By the Gauss-Jordan method, in the original place you will have the identity and in the place that the identity currently is you will have the inverse matrix:

So, let's start by setting the first row element to 0 in the second and the third line.

The first row element of the third line is already at zero, so no changes there. In the second line, we need to do:

L2 = L2 + 3L1

So now we have the following matrixes.

1 -1 2        |            1 0 0

0 -1 7       |            3 1 0        

0  4 -25   |            0 0 1

Now we need the element in the second line, second row to be 1. So we do:

L2 = -L2

1 -1 2        |            1 0 0

0 1 -7       |            -3 -1 0        

0  4 -25   |            0 0 1

Now, in the second row, we need to make the elements at the first and third line being zero. So, we have the following operations:

L1 = L1 + L2

L3 = L3 - 4L2

Now our matrixes are:

1 0 -5       |            -2 -1 0

0 1 -7       |            -3 -1 0        

0 0 3       |            12 4 1

Now we need the element in the third line, third row being one. So we do:

L3 = -L3

1 0 -5       |            -2  -1     0

0 1 -7       |            -3  -1      0        

0 0 1       |            4    (4/3) (1/3)

Now, in the third row, we need the elements in the first and second line being zero. So we do:

L1 = L1 + 5L3

L2 = L2 + 7L3

So we have:

1 0 0 |       18  -(17/3)   (5/3)

0 1 0 |       25  (25/3)  (7/3)

0 0 1 |       4    (4/3)     (1/3)

So the inverse matrix is:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

4 0
3 years ago
Whenever she visits Oakdale, Karin has to drive 55 kilometres due north from home. Whenever she visits Brookfield, she has to dr
Natalija [7]
Sorry it is a bit messy but the answer is right

6 0
2 years ago
Read 2 more answers
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