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algol [13]
2 years ago
9

Factor x2 + 10x + 25

Mathematics
2 answers:
Vanyuwa [196]2 years ago
7 0
X=-5 i hope this helpsss
igor_vitrenko [27]2 years ago
4 0

Answer:

(x+5)(x+5)

Step-by-step explanation:

x²+10x+25

25

/ \

+5 and +5

(x+5)(x+5)

if you dont understand. I recommend this video https://youtu.be/yBCAv_NzzPQ

at 10:21

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BARSIC [14]

Answer:

Step-by-step explanation:

i'm sure the answer is C

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3 years ago
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makayla wanted to buy cookies for the class the cookies are in 1 package? how many cookies are in 10 packages how many cookies i
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Answer:

you didn't put how many cookie are in one package

Step-by-step explanation:

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8 0
3 years ago
Help! <br><br>3x10=(2x10)+(1x_)
motikmotik
3*10=(2*10)+(1*x) \\  \\ 30=20+x \\  \\ 10=x
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3 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
If f (x) = 2x + 1, then, f (3)
Mashutka [201]

Answer:

x=1

Step-by-step explanation:

3 0
3 years ago
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