Question

It is highly likely that Malika will randomly select the letter A from a group of letters. From which group of letters could Malika be selecting?
A. A, E, I, O, U
B. A, B, C, A, D
C. A, F, A, G, A, H
D. A, A, J, A, A, K

Answer 1

Answer:

D. A, A, J, A, A, K

Step-by-step explanation:

It is given that it is highly likely that Malika will randomly select the letter A from a group. This means, there is a very high probability of selecting the letter A from the group. So, for all the given options we have to find what is the probability of randomly selecting the letter A.

Option A:

Total letters = Total Possible Outcomes = 5

Occurrence of A = Total Favorable Outcomes = 1

Since, probability is equal to Total Favorable Outcomes divided by Total Possible outcomes, the probability of selecting A in this case would be = $\frac{1}{5}$ = 0.2

Option B:

Total letters = Total Possible Outcomes = 5

Occurrence of A = Total Favorable Outcomes = 2

The probability of selecting A in this case would be = $\frac{2}{5}$ = 0.4

Option C:

Total letters = Total Possible Outcomes = 6

Occurrence of A = Total Favorable Outcomes = 3

The probability of selecting A in this case would be = $\frac{3}{6}$ = 0.5

Option D:

Total letters = Total Possible Outcomes = 6

Occurrence of A = Total Favorable Outcomes = 4

The probability of selecting A in this case would be = $\frac{4}{6}$ = 0.67

Hence, from option D, we have the highest probability of selecting the letter A from given letters.

Therefore, Malika would be selecting from the group in option D. A, A, J, A, A, K