Answer: 9:3:3:1 and approximately
Explanation: just did it
Answer: Hello your question is incomplete below is the complete question
Let’s look at a different gene locus, we’ll call it B. The normal, wild type, the population was 100% BB. There are 150 Pakicetus in the population at present. Assume Charles had another mutation; this one at the B locus, to produce allele b. What is the gene frequency of allele b in the population if the population of Pakicetus reaches 100,000
answer : ≈ 1
Explanation:
<u>Determine the Gene frequency of allele b </u>
Population = 100,000
There are 150 Pakicetus in population i.e. 300 alleles at locus B
hence the frequency of b = 1/300 = 0.33%
Increase in population does not affect frequency of b ( HW equilibrium )
<em>therefore the Gene frequency of allele b </em>
= 0.33% * 0.33% * 100000 = 1.08
≈ 1
Answer:
D making a conclusion as they are telling you what they found
