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VikaD [51]
2 years ago
13

PLEASE HELP FAST!!! Estimate the line of best fit using two points on the line.

Mathematics
2 answers:
yawa3891 [41]2 years ago
4 0

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}=xy_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, 8) and (x₂, y₂ ) = (8, 5)

m = \frac{5-8}{8-2} = \frac{-3}{6} = - \frac{1}{2}

The line crosses the y- axis at (0, 9) ⇒ c = 9

y = - \frac{1}{2} x + 9 → D

FrozenT [24]2 years ago
3 0

Answer:

D) y= -1/2x+9

Step-by-step explanation:

if u substitute y with 8 u will get 2

if u substitute y with 5 u will get 8

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What is the wave speed of a wave that has a frequency of 200 Hz and a wavelength of 0.40 m?
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Step-by-step explanation:

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The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.8, 15.6, 15.1, 15.2, 15.1, 15.5, 15.9, 15.5. C
Bingel [31]

Answer:

The required 97.5% confidence interval is

\text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\\text {CI} = 15.5 \pm 2.8412\cdot \frac{0.31}{\sqrt{8} } \\\\\text {CI} = 15.5 \pm 2.8412\cdot 0.1096\\\\\text {CI} = 15.5 \pm  0.311\\\\\text {CI} = 15.5 - 0.311, \: 15.5 + 0.311\\\\\text {CI} = (15.19, \: 15.81)\\\\

Therefore, we are 97.5% confident that the actual mean amount of juice in all such bottles is within the range of 15.19 to 15.81 ounces

.

Step-by-step explanation:

The amounts (in ounces) of juice in eight randomly selected juice bottles are:

15.8, 15.6, 15.1, 15.2, 15.1, 15.5, 15.9, 15.5

Let us first compute the mean and standard deviation of the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = 15.5

=STDEV(number1, number2,....)

The standard deviation is found to be

s = 0.31  

The confidence interval for the mean amount of juice in all such bottles is given by

$ \text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $\\\\

Where \bar{x} is the sample mean, n is the samplesize, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 97.5% confidence level.

The t-score corresponding to a 97.5% confidence level is

Significance level = α = 1 - 0.975 = 0.025/2 = 0.0125

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.0125 and DoF = 7

t-score = 2.8412

So the required 97.5% confidence interval is

\text {CI} = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\\text {CI} = 15.5 \pm 2.8412\cdot \frac{0.31}{\sqrt{8} } \\\\\text {CI} = 15.5 \pm 2.8412\cdot 0.1096\\\\\text {CI} = 15.5 \pm  0.311\\\\\text {CI} = 15.5 - 0.311, \: 15.5 + 0.311\\\\\text {CI} = (15.19, \: 15.81)\\\\

Therefore, we are 97.5% confident that the actual mean amount of juice in all such bottles is within the range of 15.19 to 15.81 ounces.

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Answer:

Step-by-step explanation:

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