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3 years ago

Triangle A B C is shown. The length of A B is 12, the length of B C is 24, and the length of C A is 12 StartRoot 3 EndRoot

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

Answer: The answer is B.

Step-by-step explanation:

First of all, if you just look at the angles, you can already tell that angle A is the right angle, in which you can then cross out A and C. Now you are down to B or D. This was tough but if you remember that the longer leg is square root of 3 times the shorter leg then you can tell that the included angle between the side showing 12 and the side showing 24 is the 60 degree angle. This leaves you to tell that the other angle is 30 degrees.

I hope this helps ;)

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laiz [17]

Answer:

Step-by-step explanation:

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3 years ago

Please help me fast i am giving 14 points for 5 questions. (Geometry) Thank you so much!

algol13

1 ) Area of the rectangle:
A = L x W
L = √(2² + 2²) = √8 = 2√2
W = √(6² + 6²) = √72 = 6√2
A = 2√2 x 6√2 = 24 units²
2 ) Area of a triangle:
RQ = 2 + 4 = 6 units
h = 4 units
A = ( 6 * 4 ) / 2 = 12 units²
3 ) The perimeter of Δ ABC:
AB = √(3² + 4²) = √25 = 5 units
BC = √(1² + 1²) = √2 = 1.4 units
AC = √(3² + 4²) = √25 = 5 units
P = 5 + 1.4 + 5 = 11.4 units
4 ) Area of the figure ( approx.):
A ≈ ( 8 * 8) - 6.25 - 8 - 2.5 ≈ 47.25
Answer: C ) 50 ft²
5 ) Area under the curve:
A ≈ 0.5 * 3 + 0.5 * 3.5 + 0.5 * 4 + 0.5 * 4.5 + 0.5 * 5 + 0.5 * 4.5 + 0.5 * 4 +
+ 0.5 * 3 ≈ 0.5 * 31.5 ≈ 15.6
Answer: B ) 15 units²

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Step-by-step explanation:

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Answer:

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Step-by-step explanation: hoped this helps

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2 years ago

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

7 0

3 years ago