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2 years ago

Triangle A B C is shown. The length of A B is 12, the length of B C is 24, and the length of C A is 12 StartRoot 3 EndRoot

Mathematics

1 answer:

jeka57 [31]2 years ago

8 0

Answer: The answer is B.

Step-by-step explanation:

First of all, if you just look at the angles, you can already tell that angle A is the right angle, in which you can then cross out A and C. Now you are down to B or D. This was tough but if you remember that the longer leg is square root of 3 times the shorter leg then you can tell that the included angle between the side showing 12 and the side showing 24 is the 60 degree angle. This leaves you to tell that the other angle is 30 degrees.

I hope this helps ;)

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1) the sum of three consecutive integers even is 3,2,1. find the integers.

BabaBlast [244]

3)The original rational number was 17/12.

4)The age of Ruby and Reshma are 20 and 28 years respectively.

Explanation:

3)Let the numerator be x.

So denominator will be (x - 5)

If we add 5 to numberator then it will be (x + 5)

New number is (x + 5)/(x - 5)=11/6

Solve for X by cross multiplying

6(x + 5)=11(x - 5)

6x + 30=11x - 55

5x=85

x=17

So original rational number was 17/12.

4)The ages of Ruby and Reshma are in the ratio 5:7

So, let the present ages of Ruby and Reshma be 5x and 7x respectively.

Also, it is given that four years from now the ratio of their ages will be 3:4

So, the equation - 5x + 4 / 7x + 3 = 3/4

⇒4(5x+4)=3(7x+4)

⇒20x+16=21x+12

⇒21x−20x=16−12

⇒x=4

⇒5x=20 and 7x=28

The age of Ruby and Reshma are 20 and 28 years respectively.

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1 year ago

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Step-by-step explanation:

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3 years ago

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2 years ago

Read 2 more answers

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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3 years ago

The Pythagorean theorem is a2+b2=c2. Solve for b.

nata0808 [166]

Answer:

b = √c²-a²

Step-by-step explanation:

b² = c² - a²

b = √c²-a²

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