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vitfil [10]
3 years ago
6

What figures can be drawn in a circle with 2 perpendicular diameters?

Mathematics
1 answer:
nalin [4]3 years ago
5 0
A little washer on wine cap
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You are making fruit baskets using 54 apples, 36 oranges, and 73 bananas. a. Explain why you cannot make identical fruit baskets
GrogVix [38]
Question 1:
73 is a prime number. It can only be divided by 1 and by itself. 

The GCF of the three numbers:
 54                               36                            73
1×54                           1×36                          1×73
2×27                          2×18
3×18                           3×12
6×9                            4×9
                                   6×6

GCF of 54, 36 and 73  is 1

GCF of 54 and 36 is 18

If we divide 54 apples into 18 baskets, we have 3 apples in each basket
If we divide 36 oranges into 18 baskets, we have 2 oranges in each basket
If we divide 73 bananas into 18 baskets, we have 4 bananas in each basket + one banana left over.

So the greatest number of identical fruit baskets we can make with the least amount of fruit left over is 18 baskets
6 0
3 years ago
Find the slope of a line that passes through the following points<br> (-1,-5), (3,-3)
svet-max [94.6K]

Answer:

m=\frac{1}{2}

Step-by-step explanation:

defition of  slope(m) of a line:

m=\frac{Y_b-Y_a}{X_b-X_a}

A=(-1,-5)=(Xa,Ya)  then Xa= -1 and Ya= -5

B=(3,-3)=(Xb,Yb) then  Xb=3 and Yb= -3

m=\frac{-3-(-5)}{3-(-1)} \\\\m=\frac{-3+5}{3+1} \\\\m=\frac{2}{4} \\\\m=\frac{1}{2}

8 0
2 years ago
You roll a six-sided number cube (die). What is the BEST answer for the probability that the number rolled is between 1 and 6, i
posledela

Answer: It is A certain.

Step-by-step explanation:

Because all the numbers on a six-sided cube is between 1 and 6 so it is certain or 100/100 that the number will land on a number between 1 and 6.

4 0
3 years ago
2/3(4w+9) Please help
vfiekz [6]
Change the y to w the app didnt have the letter w so i just had to choose another letter

8 0
3 years ago
Write a two-column proof.
-Dominant- [34]

Proof:-

In ∆XYZ and ∆VWZ

\because\sf\begin{cases}\sf XZ\cong VZ(Given)\\ \sf YZ\cong WZ(Given)\\ \sf

Hence

∆XYZ\cong(Side-Angle-Side)

7 0
2 years ago
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