Y=mx+b where m=slope=(dy/dx) and b=y-intercept (value of y when x=0)
You have two points...(1,-2),(3,2) so
m=(y2-y1)/(x2-x1)=(2--2)/(3-1)
m=4/2=2 now that you have the slope...
y=2x+b, you can use either point to solve for the y-intercept, I'll use (3,2)
2=2(3)+b
2=6+b
b=-4 so the line is:
y=2x-4
Answer:
1. y+5=4x-40
2.y=4x-45
Step-by-step explanation:
To get the slope of a line you do y₂-y₁/x₂-x₁ so we plug in the values -9+5/9-10 and we get -4
Point-slope form states y-y₁=m(x-x₁) where m is the slope so plug in the values we get y+5=4(x-10) and you get y+5=4x-40 then turn this equation into y=mx+b and get y= 4x-45
I think the answer is maximum