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Juliette [100K]
3 years ago
13

Out of 1,400 students, 60% have a dog. How many students have a dog in part ?

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

840 students

Step-by-step explanation:

0.6 * 1400 = 840 students

Zigmanuir [339]3 years ago
6 0

Answer:

840

Step-by-step explanation:

60% of 1400 is 840

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Which statements apply to the expression
bagirrra123 [75]

Answer:

A, C, D, F

Step-by-step explanation:

Given the expression : (3/5)³

Recall :

a^b where, a = base ; b = exponent

In ; (3/5)^3

Base = 3/5 ; exponent = 3

Similarly ;

a^b = a in b places

(3/5)^3 = (3/5) * (3/5) * (3/5)

(3/5) * (3/5) * (3/5) = (3*3*3) / (5*5*5) = 27/125

Hence, A, C, D and F are all correct

7 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY HOMEWORK.
Anna71 [15]

Answer:

Check pdf

Step-by-step explanation:

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7 0
3 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Gail can use her 12% employee discount once a week. Last Sunday, she bought a $45 sweater at 1/3 off and used her discount on th
NNADVOKAT [17]

Statement 1 : Gail bought a $45 sweater at 1/3 off.

<u>Discount in Sweater Purchase:</u>

\frac{1}{3} \; of \; 45 = \frac{1}{3} \times 45 \; = \;\frac{45}{3} =\$15

Statement 2: Gail can use her 12% employee discount once a week and used her discount on the suit priced at $140.

Discount in Suit Purchase:

12\% \; of \; 140 =\frac{12}{100}  \times  140 = 0.12 \times 140 = \$16.8

Conclusion:

<u>Discount in Suit Purchase ($16.8) is greater than Discount in Sweater Purchase ($15)</u>

8 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (3, -2) and (9, -2)?
ICE Princess25 [194]

m=(-2+2)/(9-6)=0/3=0

m=0

7 0
3 years ago
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