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Yakvenalex [24]
3 years ago
12

When a principal amount, P, is invested at an annual interest rate,r, and compounded n times per

Mathematics
2 answers:
romanna [79]3 years ago
8 0

Answer:

2

Step-by-step explanation:

A = P( 1+r/n) ^ (nt)

P is the amount invested

r is the rate

n is the number of times per year the interest is compounded

t is the number of years

every 6 months is twice a year

so n is 2

wlad13 [49]3 years ago
6 0

Answer:

Step-by-step explanation:

10+50+60=500

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A farmer sells 8.7 kilograms of pears and apples at the farmer's market. 2 5 of this weight is pears, and the rest is apples. Ho
Ivenika [448]

Answer: 5.22kg

Step-by-step explanation:

From the question, a farmer sells 8.7 kilograms of pears and apples at the market. Of the pears and apples sold, 2/5 of this weight is pears, and the rest is apples. To calculate the kilograms of apple sold goes thus:

Total kilograms sold = 8.7kg

Fraction of pears weight = 2/5

Pears kilograms sold = 2/5 × 8.7

= 0.4 × 8.7

= 3.48kg

Since the kilograms of pears sold is , 3.48kg, to get the kilograms of apple sold, we subtract 3.48kg from 8.7kg. This will be:

= 8.7kg - 3.48kg

= 5.22kg

8 0
3 years ago
y = A system of equations. y equals StartFraction one-half EndFraction x minus 6. x equals negative 4.x – 6 x = –4 What is the s
tatiyna

Answer: (-4,-8)

Step-by-step explanation: I got a 100% on the quiz

8 0
3 years ago
Read 2 more answers
5
postnew [5]

Answer:

(2)

Step-by-step explanation:

slope:-1/2

y-intercept:1   (because the function passes (0,1))

3 0
3 years ago
2 3/4 divided by 1/2 ?
Vladimir [108]

Answer:

5.5

Step-by-step explanation:

7 0
2 years ago
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bo
Furkat [3]

Answer: B

Step-by-step explanation:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. Since the machines are identical and running at the same constant rate, it means each of them as the same rate. The rate of each machine can produce would be determined by dividing the combined unit rate by 6. It becomes

270/6 = 45 bottles per minutes

The rate for 10 machines running at the same constant rate would be

10 × 45 = 450 bottles per minutes.

If the 10 machines produce 450 bottles per minutes, then,

In 4 minutes, the 10 machines will produce 4 × 450 = 1800 bottles

4 0
3 years ago
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