When a principal amount, P, is invested at an annual interest rate,r, and compounded n times per
2 answers:
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Answer:
n = 98, that is, she scored at the 98th percentile.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
She scored 38, so
Test scores are normally distributed with a mean of 25 and a standard deviation of 6.4.
This means that
Find the percentile:
We have to find the pvalue of Z. So
has a pvalue of 0.98(rounding to two decimal places).
So n = 98, that is, she scored at the 98th percentile.
Part A.
Consider a punch containing L liters.
60% of these that is
is grape juice, and the rest, 0.4 L is lemon-soda.
so, for the variable L, the total amount of punch, the total amount of grape juice is 0.6 L
and the amount of lemon soda in the punch is 0.4L
Part B.
For L=2, we substitute and get:
0.6 L=0.6 * 2 liters = 1.2 liters of grape juice
0.4 L = 0.4 * 2 liters = 0.8 liters of lemon soda.
Consider a punch containing L liters.
60% of these that is
so, for the variable L, the total amount of punch, the total amount of grape juice is 0.6 L
and the amount of lemon soda in the punch is 0.4L
Part B.
For L=2, we substitute and get:
0.6 L=0.6 * 2 liters = 1.2 liters of grape juice
0.4 L = 0.4 * 2 liters = 0.8 liters of lemon soda.