Answer:
36/25=1 and 11/25 6/5=1 and 1/5
Step-by-step explanation:
booooooooooooooo
The answer is B if they are fractions.
3/8-1/8=2/8 or simplified 1/4
Have a good day.
Answer:
= 403
Step-by-step explanation:
the sum to n terms of an arithmetic series is
= 
(a + l) ← a is the first term and l the last term
here a = - 5 and l = 67 , then
= 
(- 5 + 67) = 6.5 × 62 = 403
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>
Answer:
sin(2A) = (2√2 + √3) / 6
Step-by-step explanation:
2A = (A+B) + (A−B)
sin(2A) = sin((A+B) + (A−B))
Angle sum formula:
sin(2A) = sin(A+B) cos(A−B) + sin(A−B) cos(A+B)
sin(2A) = 1/2 cos(A−B) + 1/3 cos(A+B)
Pythagorean identity:
sin(2A) = 1/2 √[1 − sin²(A−B)] + 1/3 √[1 − sin²(A+B)]
sin(2A) = 1/2 √(1 − 1/9) + 1/3 √(1 − 1/4)
sin(2A) = 1/2 √(8/9) + 1/3 √(3/4)
sin(2A) = 1/3 √2 + 1/6 √3
sin(2A) = (2√2 + √3) / 6
