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Arisa [49]
3 years ago
8

Someone please help me on these 2 problems!

Mathematics
1 answer:
Veronika [31]3 years ago
5 0

1) function  2) not a function

the first one is a function because its y values are the same number (3), which means it is a horizontal line and horizontal lines are functions.  

the second one is not a function because the coordinates cannot have different inputs but different outputs. each input must have only one output.

the coordinates for the second one are:

(2,5); (1,1); (1,2); (3,2)

and <u>a function cannot have two same x-coordinates</u>. it must pass the vertical line test which is a way to tell if something is a function or not. since the second graph does not pass the vertical line test, it is not a function

hope this helps :)

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Enter your answer and show all the steps that you use to solve this problem in the space provided.
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Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

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(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

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