find y=mx+b for line parallel to AB.
The line that is parallel will have the same slope as line AB:
the slope of line AB is
m=(8-3)/(-10-2)
=5/-12
=-5/12
Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).
at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.
To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so
4+4=8
Answer:
y = -x + 9
Step-by-step explanation:
The line that passes through the points (-2,4) and (0,6) has a slope of 1, and a y intercept of 6. The equation to the first line is y = x + 6. and perpendicular lines always have the opposite, reciprocal slope of the other line. So the slope for the second line would be -1. A line with the slope of -1 and a point of (5,4) would contain the points (5,4) , (4,5) , (3,6) , (2,7) , (1,8) , and (0,9) , which is the y intercept for the second line. So the equation for the second line would be y = -x + 9
Answer:
-6 & 6
Step-by-step explanation:
-6 time 6 is -36
70 is the area of the polygon
