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Kitty [74]
3 years ago
15

A cubic function with roots at 2, 0 and 3 containing the point at (5,-6)

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer:

Cubic equations and the nature of their roots

Just as a quadratic equation may have two real roots, so a cubic equation has possibly three. But unlike a quadratic equation which may have no real solution, a cubic equation always has at least one real root.

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BAYES FORMULA
djverab [1.8K]

Answer:

republicans

Step-by-step explanation:

Given, there are 60% democrats and republicans 40%

60% of the democrats voted for democrats and 95% of the republican voted for their candidate

therefore

% of votes that went for Democrats =0.6*0.6=0.36 = 36%

% of votes that went for Republics=0.4*0.95=0.38 = 38%

Since the republicans have more % of votes  thus Republic's mayor runs city hall.

6 0
3 years ago
What is the answer to this???
jolli1 [7]
The answer for the question is 4
8 0
3 years ago
What two numbers multiply to 10 and add to -29 ?
Degger [83]
Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}
x= \frac{-29+/- \sqrt{841-40} }{2}
x= \frac{-29+/- \sqrt{801} }{2}
x= \frac{-29+/- 3\sqrt{89} }{2}

x= \frac{-29- 3\sqrt{89} }{2} or \frac{-29+ 3\sqrt{89} }{2}
those are the 2 numbers
aprox=-28.65 and -0.349


5 0
3 years ago
Read 2 more answers
The difference between 2 numbers is 26 and one number is 3 Times the other​
Aleks04 [339]

Answer:

Let the numbers be

x \: and \: 3x

Then,

ATQ

3x - x = 26

2x = 26

x = 13

3x = 39

3 0
3 years ago
5) Jeff has a set monthly housing budget of $812. If Jeff is in an 18% tax bracket and his
Greeley [361]

Answer:

2.406%

Step-by-step explanation:

28600*18%=5148

$5148-28600=$23,452

$23452/12 months=$1954.33 a month take home

1954.33/812=2.406%

6 0
4 years ago
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