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3 years ago

15

A cubic function with roots at 2, 0 and 3 containing the point at (5,-6)

1 answer:

natulia [17]3 years ago

5 0

Answer:

Cubic equations and the nature of their roots

Just as a quadratic equation may have two real roots, so a cubic equation has possibly three. But unlike a quadratic equation which may have no real solution, a cubic equation always has at least one real root.

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What is the element a^23 in matrix A? <br> A=8 -4 -3<br> 3 -9 -5<br> -8 8 8

labwork [276]

8 -4 -3
3 -9 -5-8 8 8

This is a matrix of 3 rows and 3 columns (it's called square matrix because the number of rows = the number of columns)

To localise an element of a matrix we use indices R and C, the first index being ALWAYS the row and the second, ALWAYS the column.

Hence:
A₂₃ = the element in row 2 and column 3, that is - 5

COLUMN
1st 2nd 3rd
--------------------------------
1st | 8 -4 -3
ROW 2nd | 3 -9 -5 3rd |-8 8 8

4 0

3 years ago

Read 2 more answers

The total surface area of a cylinder is 690.8. Its diameter is 10 inches. What is it’s height?

AysviL [449]

Answer:

$h=17\ in$

Step-by-step explanation:

we know that

The total surface area of a cylinder is equal to

$SA=2\pi r^{2}+2\pi rh$

where

r is the radius of the base of cylinder

h is the height of cylinder

we have

$SA=690.8\ in^2$

$r=10/2=5\ in$ ----> the radius is half the diameter

assume

$\pi=3.14$

substitute the given values and solve for h

$690.8=2(3.14)(5^{2})+2(3.14)(5)h$

$690.8=157+31.4h$

Solve for h

$31.4h=690.8-157$

$31.4h=533.8$

$h=17\ in$

7 0

3 years ago

MP bisects ∠BMS. If m∠BMP = 2x + 9 and m∠BMS = 7x – 3, find the value of m∠PMS

dimulka [17.4K]

Answer:

Step-by-step explanation:

If MP bisects ∠BMS, then the line MP divides <BMS equally;

The adition postulate if therefore true;

<BMP +< PMS = <BMS and <BMP = < PMS

The equation becomes;

<BMP +< BMP= <BMS

2 <BMP = <BMS

2(2x+9) = 7x - 3

4x+18 = 7x-3

collect like terms

4x-7x = -3-18

-3x = -21

x = 21/3

x = 7

Since <BMP = < PMS 2x+9

< PMS = 2(7)+9

< PMS = 14+9

< PMS = 23

Hence the value of < PMS is 23

3 0

3 years ago

Find the absolute maximum value for the function f(x) = x^2 − 4, on the interval [–3, 0) U (0, 2].

Andreyy89

Answer:

5

Step-by-step explanation:

The function $y=x^2 -4$ is

decreasing for all $x\in [-3,0);$
is increasing for all $x\in (0,2]$

(see attached diagram for details).

The maximum value of the function is at endpoints -3 or 2. find y(-3) and y(2):

$y(-3)=(-3)^2-4=9-4=5\\ \\y(2)=4^2-4=0$

So, the maximum value is 5.

5 0

3 years ago

Use the figure and given angle to find the measure of each angle below (tell me how many degrees it is).

Minchanka [31]

9514 1404 393

Answer:

∠6 = ∠4 = 84°

∠5 = ∠3 = 96°

Step-by-step explanation:

Angle 4 and the marked angle (84°) are <em>corresponding</em> angles, so are congruent. Angles 4 and 6 are vertical angles, so are congruent.

∠6 = ∠4 = 84°

Angle 3 and the marked angle are a linear pair, so angle 3 is the supplement of 84°:

∠3 = 180° -84° = 96°

Angle 3 and angle 5 are <em>alternate interior </em>angles, so are congruent.

∠5 = ∠3 = 96°

3 0

3 years ago