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3 years ago

A cubic function with roots at 2, 0 and 3 containing the point at (5,-6)

Mathematics

1 answer:

natulia [17]3 years ago

5 0

Answer:

Cubic equations and the nature of their roots

Just as a quadratic equation may have two real roots, so a cubic equation has possibly three. But unlike a quadratic equation which may have no real solution, a cubic equation always has at least one real root.

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Solve the equation:

adelina 88 [10]

Answer:

x=1 is the correct answer

7 0

3 years ago

Read 2 more answers

The proportion of defective computers built by Byte Computer Corporation is 0.15. In an attempt to lower the defective rate, the

FinnZ [79.3K]

Answer:

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b) Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

c) Calculate the value of the test statistic = 0.991

d) The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Null hypothesis accepted at 0.01 level of significance

f) we accepted null hypothesis.

Hence the proportion of defective item of computer has been lowered.

Step-by-step explanation:

Step(i):-

Given the sample size 'n' = 42

Given random sample of 42 computers were tested revealing a total of 4 defective computers.

The defective computers 'x' = 4

The sample proportion of defective computers

$p = \frac{x}{n} = \frac{4}{42} = 0.095$

Given The Population proportion 'P' = 0.15

The level of significance ∝=0.01

Step(ii):-

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

$Z = \frac{0.095-0.15}{\sqrt{\frac{0.15(0.85)}{42} } }$

$z = \frac{-0.055}{\sqrt{0.00303} } = - 0.9991$

Calculate the value of the test statistic Z = - 0.9991

|Z| = |- 0.9991| = 0.991

Step(iii):-

The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Calculate the value of the test statistic Z = 0.991 < 2.57 at 0.01 level of significance.

Conclusion:-

Hence the null hypothesis is accepted at 0.01 level of significance.

The proportion of defective item of computer has been lowered.

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3 years ago

What would 2 x (x-3) sum be

brilliants [131]

Answer:

2x-6 I think

Step-by-step explanation:

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2 years ago

State whether either extreme in the data set is an outlier.

Paladinen [302]

B neither are outliers

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3 years ago

How many milliliters are in 5 liters?

blsea [12.9K]

Answer:

There are 5000 mililitres in 5 litres

Therefore option A.

Hope u got the answer............

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3 years ago