Answer:
$3.10
Step-by-step explanation:
Their GCF is 6 and the sum is 66
Step-by-step explanation:
Answer:
35/132.
Step-by-step explanation:
There are a total of 12 balls. So:
Prob(First is green) = 5/12.
After the first selection there are 11 balls left.
Prob(The second is red) = 7/11.
The required probability = 5/12 * 7/11
= 35/132.
Note: the probabilities are multiplied because the 2 events are independent.
Question:Round the decimal to the nearest hundredth;then write it as a percentage
<span>Problem: 0.4612=___(<rounded)=___(<percentage)
</span>0.4612 =~ 0,46 (rounded) = 0,46 = 46 (percentage)
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y. the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y. We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128. Let's reduce this by dividing all three terms by 4: 2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32. The formula for area is A = L * W. Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y. The area of the patch is (x)(-2x+32) = A. We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation. Remember the formula x = -b/(2a)? Once you have calculated this x, subst. your value into the formula for y: y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero. This approach should give you the same x value as before; the corresponding y value will be the same; y=-2x+32.
Multiply x and y together. That'll give you the maximum possible area of the garden patch.
