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Nitella [24]
3 years ago
11

Alan invests $2500 in two different accounts. The first account paid 9 %, the second account paid 8 % in

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0

Answer:

I think its at 8%

Step-by-step explanation:

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USING YOUR MATH
Eddi Din [679]

Answer:

area = \pi {r}^{2}  \\  =  \frac{22}{7} ( { \frac{22}{2} )}^{2}  \\  = 380 \: sq \: feet

8 0
3 years ago
Express 5×-4y=20 in the form a×+by+c=0and write the value of a,band c<br><br>​
finlep [7]

Answer:

a = 5

b = -4

c = -20

Step-by-step explanation:

Here, we want to express the given equation in the following form;

So we can have this as;

5x-4y-20 = 0

That means we have;

a as 5

b as -4

and c as -20

4 0
3 years ago
You are selling tickets to your school fair to raise money for the honor society. Student tickets cost $4 and adult tickets cost
inysia [295]

If 480 tickets cost $2580, 1 student ticket is $4, 1 adult is $6. Lets try dividing. 2580/6 and 2580/4. 2580/6=$430 and 2580/4=$645 again. 4 dollars per student and 6 dollars per adult. for the students, I would say approx. of 215 student tickets sold. And for the adults 215 dollars as well. to know this, I looked up multiples of them both. and 215 was the common one. So 215 adult tickets were sold and 215 student tickets were sold

4 0
3 years ago
$600 invested at 5% compounded daily after a period of 3 years.
alisha [4.7K]

Answer:

$697.09

Step-by-step explanation:

The computation of the investment after 3 years is shown below:

As we know that

Amount = Present value × (1 + rate)^number of years

= $600 × (1 + 0.05 ÷ 365)^365× 3

= $697.09

Hence, the investment after 3 years is $697.09

We simply used the above formula to determine the investment

5 0
3 years ago
Expand: In 2a^3/b^4
Ket [755]

Answer:

  ln(2) +3ln(a) -4ln(b)

Step-by-step explanation:

  \ln{\left(\dfrac{2a^3}{b^4}\right)}=\ln{(2a^3b^{-4})}=\ln{(2)}+\ln{(a^3)}+\ln{(b^{-4})}\\\\=\boxed{\ln{(2)}+3\ln{(a)}-4\ln{(b)}}

__

The applicable rules of logarithms are ...

  log(ab) = log(a)+log(b)

  log(a^b) = b·log(a)

3 0
4 years ago
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