D) The median of 2nd Period is greater than the median of 1st Period.
The one that's true
Hope this helps!
The classes could each have proportions of 5 boys to 6 girls, but they don’t necessarily have to be exactly 5 to 6. The number could 5 to 6 for one class, but it could also be 10 to 12 for another class, since 10 to 12 is a scale factor of 5 to 6.
√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)
Answer:
28 different ways
Step-by-step explanation:
This is a combination question. Combination has to do with selection.
Total number of element in the set = 8
Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}
Total number divisible by 6 or 8 is 6
The number of ways we can choose 6 items from 8 is expressed as;
8C6 = 8!/(8-6)!6!
8C6 = 8!/(2)!6!
8C6 = 8*7*6!/2!6!
8C6 = 8*7/2
8C6 = 56/2
8C6 = 28 ways
Hence there are 28 different ways
Answer: B. y = 2x-5 is your answer hope this helped
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Step-by-step explanation:
