Find the interquartile range (IQR) for the following data set:

Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use

viktelen [127]

For this case we have the following equation:
d = 0.5 + 5t
We will describe the equation step by step.
0.5: Initial distance Jillian walked
5: speed with which Jillian begins to jog
t: independent variable that indicates the number of hours
y: dependent variable that indicates the distance traveled in miles
Answer:
The variable variable is time and the dependent variable is distance.

3 0

2 years ago

Read 2 more answers

A new superhero movie has its first showing and there are 155 people in line to see it. If the ratio of kids to adults waiting t

lidiya [134]

The number of adults waiting to see the new superhero movie is 62.

<h3>How many adults are waiting in line?</h3>

Ratio expresses the relationship between two or more numbers. Ratio is used to compare two or more numbers. It shows the number of times that one value is contained in another value.

Looking at the ratio given in this question, we know that there are 1 1/2 (3 /2) more children than adults on the line to watch the new superhero movie.

Number of adults waiting to see the movie = (ratio that represents adults / sum of ratio) x total number of people wafting in line

Sum of ratios = 2 + 3 = 5

(2/5) x 155 = 62 people

To learn more about ratios, please check: brainly.com/question/25927869

#SPJ1

3 0

1 year ago

In triangle ABC, and C is a right angle. Find the value of the trig function find the sec(A) if C=25, B=20, A=15

asambeis [7]

Answer:

sec A = 5/4

Step-by-step explanation:

Sec of an angle is hypotenuse/adjacent side

In your problem, sec A = 25/20 = 5/4

It helps if you can draw a figure of the problem. Make sure you memorize the definition of each trig function

5 0

2 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$