Answer:
i have NO CLUE on what you said at the beginning but the slope is 2
Step-by-step explanation:
point 1 is the origin and point two is (1, 2). using this trick called rise over run, i "rise" two units to reach the horizontal level of (1, 2). then i'll "run" over to the point, which is one unit. rise = two units and run = one unit so rise/run is 2
hope this helps!
So the equation for the volume of the sphere is
![V= \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B4%7D%7B3%7D%20%20%5Cpi%20r%5E3)
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For this, you'll need to plug in 128 pi into the volume placeholder and solve for r.
![128 \pi = \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=128%20%5Cpi%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3)
Firstly, divide by pi on each side of the equation to cancel out pi. Your equation will look like this:
![128=\frac{4}{3}r^3](https://tex.z-dn.net/?f=128%3D%5Cfrac%7B4%7D%7B3%7Dr%5E3)
Next, you'll want to multiply 3/4 on each side to cancel out 4/3. Your equation will look like this:
![96=r^3](https://tex.z-dn.net/?f=96%3Dr%5E3)
Lastly, you'll want to 3rd root each side of the equation, and your answer should be
![4.58=r](https://tex.z-dn.net/?f=4.58%3Dr)
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The correct option is B. 4.58
F=94°. Angles in a quadrilateral add up to 360°,so we subtract all given angles from 360 to get 94
Answer:
the integer in question lies between 13 and 14.
Step-by-step explanation:
Review the perfect squares in the neighborhood of 194. The first that came to my mind was 225 (the squre of 15), and then 196 (the square of 14), and then 169, the square of 13.
Since 169 < x^2 < 196, the integer in question lies between 13 and 14.
Check with a calculator: √194 ≈ 13.93
9514 1404 393
Answer:
No
Step-by-step explanation:
The graph is not a straight line with define slope, so does not represent a linear function.
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The graph has segments that are straight lines. It is what we call "piecewise linear."