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mote1985 [20]
3 years ago
14

Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the

pre-image if the coordinates of point D’ in the image are (9, –8)?
Mathematics
2 answers:
MAXImum [283]3 years ago
6 0

Answer:

(13,-23)

Step-by-step explanation:

DID IT ON EDGE 2020

Vitek1552 [10]3 years ago
3 0

Answer:

D = (13, - 23 )

Step-by-step explanation:

Given the translation rule

(x, y ) → (x - 4, y + 15 )

To go in the reverse direction, that is image to original, then, reverse the operations in the translation rule.

(x , y ) → (x + 4, y - 15 ) , thus

D'(9, - 8 ) → D(9 + 4, - 8 - 15 ) → D(13, - 23 )

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4 years ago
Read 2 more answers
21. Randy owns a computer store. In 1990, he sold 150 monitors. In 2000, he sold 900
lutik1710 [3]

Answer:

y=75x+150

Step-by-step explanation:

Let y represent the number of monitors sold.

Given:

x is the number of years since 1990.

So, for the year 1990, x=0.

For the year 2000, 10 years passed. So, x=10.

Now, monitors sold in 1990 are 150. So, at x=0,y=150

Monitors sold in 2000 are 900. So, at x=10,y=900

Thus, the two points are (0,150) and (10,900).

The slope of a line with points (x_{1},y_{1}) and (x_{2},y_{2})  is given as:

Slope, m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

For the points (0,150) and (10,900), the slope is given as:

Slope, m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\ m=\frac{900-150}{10-0}\\ m=75

Now, the y-intercept is the point where x=0. So, the point (0,150) has x value as 0.

So, the y-intercept is 150.

Equation of a line in slope-intercept form is given as:

y=mx+b

Where, m is the slope and b is the y intercept.

Here, m=75 and b=150.

Therefore, the equation that represents the above data is given as:

y=75x+150

7 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

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A recipe for soup calls for 2 cups of black beans for
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Answer:

16 cups

Step-by-step explanation:

5x8=40

2x8=16

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