Which ordered pair would form a proportional relationship with the point graphed below ?

Mathematics

1 answer:

Harman [31]3 years ago

4 0

Answer:

(-30, 10)

Step-by-step explanation:

if you multiply both -20 and 60 by -0.5 you get 10 and -30 respectively. being the only pair of numbers achievable by the proportion property.

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Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. The length of the yard is 10 feet

Cerrena [4.2K]

The length of the yard is 25ft.

In order to find this we first need to set up variables for the length and the width. Since we don't know anything about the width, we'll set it as x. Then, we know the length is equal to ten more than three times the width. Since the width is x, we can write the length as 3x + 10. Now we can use the formula for the perimeter of a rectangle to solve for x.

2l + 2w = P

2(3x + 10) + 2(x) = 60

6x + 20 + 2x = 60

8x + 20 = 60

8x = 40

x = 5

Now that we have a value for x, we can plug into the length equation and find the length.

3x + 10

3(5) + 10

15 + 10

8 0

3 years ago

Subtract using a number line. −3−(−7) Select the point on the number line to plot the answer.

Igoryamba

Answer:

-3-(-7)

when subtracting a negative the signs turn in to addition

-3+(+7)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

(1 point) Find an equation of the largest sphere with center (5,3,5)(5,3,5) and is contained in the first octant. Be sure that y

Hoochie [10]

Answer:

x^2+y^2+z^2-10x-6y-10z +50 =0

Step-by-step explanation:

Given that a sphere is contained in the first octant

Centre of the sphere is given as (5,3,5)

Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes

When it touches we can get the maximum sphere

We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.

Hence radius =3

Equation of the sphere would be

$(x-5)^2 +(y-3)^2+(z-5)^2 = 3^2\\x^2+y^2+z^2-10x-6y-10z +50 =0$