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Zina [86]
3 years ago
6

Help please ASAP thanks

Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:   71º

Step-by-step explanation:

I cant remeber the therum but basically its just the opposite, super simple!!

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The table shows values for functions f(x) and g(x) .
Rama09 [41]

Answer:

x=-1 and x=1

Step-by-step explanation:

all you have to do is replace the letters with numbers and

5 0
3 years ago
2(3²+4²)=? <br><br><br><br><br> WHATS THE ANSWER
yulyashka [42]

Answer:

50

Step-by-step explanation:

P- Parenthesis

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction

(3²+4²)

3*3= 9     4*4= 16     16+9= 25      2(25)      25*2= 50

Hope this helped! (ノ◕ヮ◕)ノ*:・゚✧

( ゚д゚)つ Bye

7 0
2 years ago
Solution to 3x = 156
Natali5045456 [20]

Answer:

x=52

Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
Differentiate <br> \[\ln \sin^2 x\]
iragen [17]
Y = ln {[sin(x)]^2}

use the chain rule

y' = 1 /[sin(x)]^2 * 2sin(x)*cos(x) = 2cos(x) / sin(x) = 2 cot(x)

Answer: 2 cot(x)


7 0
2 years ago
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