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ElenaW [278]
3 years ago
9

The waiting time for customers at MacBurger Restaurants follows a normal distribution with a population standard deviation of 1

minute. At the Warren Road MacBurger, the quality-assurance department sampled 50 customers and found that the mean waiting time was 2.75 minutes. At the 0.05 significance level, can we conclude that the mean waiting time is less than 3 minutes
Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

Yes, we can conclude that the mean waiting time is less than 3 minutes.

Step-by-step explanation:

Since we want to check if the average waiting time is less than 3 minutes, we can state the statistical hypothesis as follows:

H_{0} : µ≥3

H_{a}: µ<3

The test is a lower sided.

Now we calculate the test statistic z:

z=(x-µ)/(σ/\sqrt{n})

=(2.75-3)/(1/\sqrt{50})

=-1.7678

The p-value obtained from the standard normal table is 0.0386

Since the p-value is less than the significance level (0.0386<0.05), the decision is to reject the null hypothesis. so there is enough evidence to conclude that the mean waiting time is less than 3 minutes.

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natta225 [31]
With finding the data that falls below a percentage, you need to look closely at the words. 

Notice that it said  25% of... that word "of" means to multiply. But, what are you multiplying? Well, if you look more closely at the plot, you'll see that your dot and line is lying on 58. But make sure you put 25 over 100.
 
So, your equation would be set up like this: 58 ÷ x = 100/25
We're using "x" as our way of saying, "We need to find out this number." 

After that, we'll need to multiply both sides of the equation by "x"
 
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Now that you have your equation, you'll need to divide both sides by 4 to get "x". 

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Problem

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