Help on this due soon, will give brainliest

Which expression is equivalent to −34÷(−812)?

tatyana61 [14]

Answer:

Step-by-step explanation:

hello :

−34÷(−812) means : -34/-812 = 17/406

8 0

3 years ago

Lance is selling T-shirts for $10 each and hats for $12.50 each. He wants to earn at least $400 per week to cover his expenses.

Andreyy89

Answer:

Step-by-step explanation:32 HATS 40 T-SHIRTS

6 0

3 years ago

David’s statement shows a previous balance of $5834.53, a payment of $150, and new transactions totaling $325. His APR is 20.4%.

DaniilM [7]

Finance charge
(5,834.53−150)×(0.204÷12)=96.64

New balance
5,834.53−150+96.64+325
=6,106.17

8 0

3 years ago

Read 2 more answers

What is the answer ?

labwork [276]

Answer:

arc VW = 66°

Step-by-step explanation:

The inscribed angle WXY is half the measure of its intercepted arc WY, so

WY = 2 × 57° = 114°

Arc YX = 180° ( semi- circle ) , then

VW = YX - WY = 180° - 114° = 66°

3 0

3 years ago

Read 2 more answers

A hypothesis test is conducted with a significance level of 10%. The alternative hypothesis states that more than 15% of a popul

Drupady [299]

Answer:

D. We cannot conclude that more than 15% of the population has at least one sibling.

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of people who has at least one sibling

$\hat p$ estimated proportion of people who has at least one sibling

$p_o=0.15$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of people who has at least one sibling is more than 0.15:

Null hypothesis: $p\leq 0.15$

Alternative hypothesis: $p > 0.15$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Let's assume that the calculated value for this case is $z_{calc}$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z> z_{calc})=0.27$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the proportion of people who has at least one sibling is not significanlty higher than 0.15.

So then the best answer for this case would be:

D. We cannot conclude that more than 15% of the population has at least one sibling.

6 0

3 years ago