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andrew-mc [135]
3 years ago
14

The value of a car decreases $500 for every 1,000 miles it is driven. The current value of the car is $23,000, and the car is dr

iven an average of 10,000 miles per year. What will be the value of the car, in dollars, at a point in time y years from now?
A) $23,000 − $500y

B) $23,000 − $0.02y

C) $23,000 − $5,000y

D) $23,000 − $0.0002y
Mathematics
1 answer:
Hoochie [10]3 years ago
4 0

Answer: C

Step-by-step explanation:

If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.

Hope this helped you and made sense! Feel free to ask me any questions you have!

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A rectangular garden has length and width as given by the expressions below.
Helen [10]
2[4 − 7(3x + 4y)] + 2[3x(−2y)]
2[4 - 21x -28y] + 2[-6xy]
8 - 42x - 56y -12xy

the perimeter of given rectangular garden is (8 - 42x - 56y -12xy).
4 0
3 years ago
Last month Albert earned half of what Betty earned, while Betty earned $5000 more than what Calvin earned. If Donna earned twice
irinina [24]

Answer:

Calving earning = 4400

Betty earning = 9400

Albert earning = 4700

Donna = 8800

Step-by-step explanation:

Given that :

Calving earning = c

Betty earning = c + 5000

Albert earning = (c + 5000) /2

Donna = 2c

c + 5000 + (c + 5000) /2 = 900 + c + 2c

c + 5000 + 0.5c + 2500 = 900 + 3c

1.5c + 7500 = 900 + 3c

7500 - 900 = 3c - 1.5c

6600 = 1.5c

c = 6600 / 1.5

c = 4400

Calving earning = c = 4400

Betty earning = 4400 + 5000 = 9400

Albert earning = (4400 + 5000) /2 = 4700

Donna = 2(4400) = 8800

5 0
2 years ago
What is the solution of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2%7D%7B4%7D%20%3D%20%5Cfrac%7Bx%2B8%7D%7B3%7D" id="TexFo
Lina20 [59]

Answer:

x = -26

Step-by-step explanation:

Multiply both sides by the lowest common multiple of 4 and 3, which is 12.

3(x+2) = 4(x+8)

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6 = x + 32 --- subtract 3x from both sides

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6 0
3 years ago
Which bacteria sample (A or B) had a smaller initial population? What was that value?
zubka84 [21]

Answer:

B has a smaller initial population of 500

Step-by-step explanation:

Given

See attachment for complete question

Required

The bacteria with the smaller initial population

The initial population is at x = 0

For bacteria A;

A(x) = 600 when x = 0

For bacteria B, we have:

B(x) = 500(2)^x

Substitute 0 for x

B(x) = 500(2)^0

B(x) = 500*1

B(x) = 500

So; when x = 0

A(x) = 600 and B(x) = 500

Because; 500 < 600

We can conclude that B has a smaller initial population of 500

4 0
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Answer:

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3.45 lbs for $ 3.58 is cheaper than 10.43 lbs for 10.23

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