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bearhunter [10]
3 years ago
5

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

tandard form.
8, -14, and 3 + 9i

Options: f(x) = x4 - 11x3 + 72x2 - 606x + 10,080
f(x) = x4 - 303x2 + 1212x - 10,080
f(x) = x4 - 11x3 - 72x2 + 606x - 10,080
f(x) = x4 - 58x2 + 1212x - 10,080
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Two events that can happen at the same time are called _______________ events.
11111nata11111 [884]

Answer:

I believe they would be called dependent events

Step-by-step explanation:

5 0
3 years ago
Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D
Ivahew [28]
Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

7 0
4 years ago
Gina plotted 3 points from the equation y = x + 2 on this coordinate grid. She drew a straight line through the points.
storchak [24]
The answer is 0,+2 is this answer
6 0
3 years ago
*BRAINLIEST* (EASY QA: Warm UP) Find a positive solution to each equation: x2 = 1/4
Georgia [21]

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's get it solved :}

  • \sf{x² = \dfrac{1}{4}}

  • \sf{x = \sqrt{\dfrac{1}{4}}}

  • \sf{x= \pm{\dfrac{1}{2}}}

  • \sf{x ={\dfrac{1}{2}} }

\textsf{[ since we need positive solution ]}

\textsf{Correct choice is C}

4 0
3 years ago
Read 2 more answers
Dayson is covering a package in the shape of a rectangular prism with wrapping paper. The package is 50 centimeters by 20 centim
goblinko [34]
<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
 1 m = 100 cm
 1 m^2 = (100 cm)^2 
 </span>1 m^2 = 10000 cm^2
 <span>The package has a surface area of cm2:
 A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
 A = <span> <span>4520 cm^2
 </span></span>The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2<span>). So, Dayson cover the package with the wrapping paper.</span>
3 0
3 years ago
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