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tatuchka [14]
2 years ago
11

Find the area of the shapes shown in the diagrams below. The lengths are in centimeters.​

Mathematics
1 answer:
RideAnS [48]2 years ago
4 0

Answer:

(a) 22cm^2

Step-by-step explanation:

(a) 6*3=18

2*2=4

4+18=22

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Help fill in the answers and are my answers rigt
Anna35 [415]

The third one tells us the price is $12 per liter, that is to say, the top number is twelve times the bottom number.

.25 × 12 = $3

.7 × 12 = $8.40

2.5 × 12 = $30

3.52 × 12 = $42.24

$57.60 / 12 = 4.80 liters

3 0
3 years ago
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Simplify the expression .
GaryK [48]
The answer is B
Hope this helps;)
6 0
3 years ago
Last year a construction worker had a gross income $ 29,700, of the which he contributed 7% to his 401(k) plain. If he got paid
AlladinOne [14]

Divide the gross income by 12 to find his monthly pay:


29,700 / 12 =$2,475 per month.


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8 0
3 years ago
75 POINTS ASAP HELP
katrin2010 [14]

Answer:

It is called the constant ratio.

3 0
3 years ago
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Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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