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miskamm [114]
3 years ago
15

HELP PLEASE

Mathematics
1 answer:
nordsb [41]3 years ago
7 0

Answer:

<h3>perpendicular line:    y = -¹/₆ x + 4¹/₃ </h3><h3>  parallel line:              y = 6x - 45 </h3>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = 6x - 7   ⇒   m₁=6

6×m₂ = -1        ⇒    m₂ = -¹/₆

 

The line y=-¹/₆ x+b passes through point (8, 3) so the equation:

3 = -¹/₆ ×8 + b must be true

3 = -⁴/₃ + b

b = 4¹/₃

Therefore equation in  slope-intercept form:

                                                     y = -¹/₆ x + 4¹/₃

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 6x - 7   ⇒   m₁=6   ⇒   m₂=6

The line y=6x+b passes through point (8, 3) so the equation:

3 = 6×8 + b must be true

3 = 48 + b

b = -45

Therefore equation in  slope-intercept form:

                                                     y = 6x - 45

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Half of 96 is 48 and they won twice as many as they lost.. how can this math problem be real XD
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A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that
kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

            Probability of winning project B = P(B) = 0.25

<u>Now, as we know that ;</u>

Probability that the company wins project A or project B = P(A \bigcup B)

              P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)

So, we have to find the value of Probability of winning project A and B, i.e;

P(A \bigcap B)

<em>Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;</em>

                    P(A \bigcap B) = P(A) \times P(B)

                                    = 0.40 \times 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

                 P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)  

                                  = 0.40 + 0.25 - 0.10

                                  = 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

3 0
3 years ago
Please help me on this thank you
fomenos
A' = (1/2)*A = (8, 0)
B' = (1/2)*B = (12, 6)
C' = (1/2)*C = (6, 8)

The third choice is appropriate.
6 0
3 years ago
There are three different colored candies:
alexira [117]

Answer:

7/20

Step-by-step explanation:

add the probabilities together and minus it by the LCM which is 20

8 0
2 years ago
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