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DerKrebs [107]
3 years ago
12

Which equation shows a proportional relationship?

Mathematics
1 answer:
Nikolay [14]3 years ago
8 0
The first one.

Hope this helps.
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Khan Academy math question. Just answer the picture
MrRissso [65]
Answer is 175
To start you need to work backwards from the mean so do 158*4 to give you the total of the revenue then simply minus what was given to get 175
Hope this helped
4 0
3 years ago
What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
3 years ago
What are the zeros of the function y = 2x2 + 5x + 2?
Dvinal [7]

Answer: not sure

but I need points

Step-by-step explanation:

JUST KIDDING It’s A I did this in school before and got it correct :)

4 0
2 years ago
Plz help I will name Brainliest
Art [367]

Answer:

question#1 = B

question#2 = A

question#3 = D

6 0
3 years ago
How to use original price and markup to find retail price? Original price is $62 and %15 mark up.. What's the retail price?
Sonbull [250]

Answer:

pretty sure its $72.94

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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