Answer: A. 2x2 - 3x - 8
Just subtract the functions and combine like terms
(f - g)(x) = f(x) - g(x)
(f - g)(x) = 2x^2 - 5 -(3x + 3)
(f - g)(x) = 2x^2 - 5 - 3x - 3
(f - g)(x) = 2x^2 - 3x - 8
Answer:
one property of log is that if the log expressions have the same base (in this case, 2), then you can multiply the added logs.
The answer would then be D
Answer:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (- 2, 3) and r = 3 , then
(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL
x² + 4x + 4 + y² - 6y + 9 = 9 ( subtract 9 from both sides )
x² + y² + 4x - 6y + 4 = 0 → A
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Answer:
a₈ = - 10935
Step-by-step explanation:
the nth term of a geometric sequence is
= a₁ 
where a₁ is the first term and r the common ratio
here a₁ = 5 and r = 
= 
= - 3 , then
a₈ = 5 × 
= 5 × - 2187 = - 10935
