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Artemon [7]
2 years ago
15

Who wants an ice cream cone this small...? I have to use this as another reference......

Mathematics
2 answers:
kenny6666 [7]2 years ago
8 0

Answer:

i will glady take one anyday

Step-by-step explanation:

its smol

spayn [35]2 years ago
4 0

Answer:

Depends on how much it costs...

Step-by-step explanation:

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Kayla went shopping for a new pair of sneakers. The listed price of the pair of sneakers was $20, but the price with tax came to
Nina [5.8K]

Hello!

\large\boxed{9 \%}

To find the percent tax, use the equation:

\text{ \% tax} = \frac{\text{ price after - initial price}}{\text{initial price}}

Substitute in the given values:

\text{ \% tax} = \frac{\text{ 21.80 - 20}}{\text{20}} \\\\\text{ \% tax} = \frac{1.80}{20} = 0.09

Multiply by 100 to find the percent tax:

0.09 * 100 = 9\%

4 0
3 years ago
20) -5(1 - 5x) +5(-8x - 2) = -4x – 8x
Alchen [17]

Answer:

x = -5

Step-by-step explanation:

-5(1 - 5x) +5(-8x - 2) = -4x – 8x

First lets simplify each side of the equation.

-5+25x-40x-10 = -4x-8x

Combine like terms

-15x-15=-12x

Add 15x to both sides (addition property of equality)

-15=3x

Divide each side by 3 (division property of equality)

x=-5

The answer is x = -5

5 0
3 years ago
HELP IM IN A QUIZZ... In a certain game, players earn 10 points for each question answered correctly and -5 points for questions
spayn [35]

Answer:

-10

Step-by-step explanation:

Just set up a simple equation.

3 0
2 years ago
Read 2 more answers
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
#1. Graph the following equation.<br> Y=6/5x + 1
TEA [102]

Answer:

6x + 1

y= 1_ 6x

it will help you

5 0
3 years ago
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