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Artemon [7]
2 years ago
15

Who wants an ice cream cone this small...? I have to use this as another reference......

Mathematics
2 answers:
kenny6666 [7]2 years ago
8 0

Answer:

i will glady take one anyday

Step-by-step explanation:

its smol

spayn [35]2 years ago
4 0

Answer:

Depends on how much it costs...

Step-by-step explanation:

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A scientist has 2/3 of liter of solution. He uses 1/2 of the solution of the solution for an experiment.
Ede4ka [16]
Remember,
To subtract 2/3-1/2 you have to make them equivalent
2/3×2-1/2×3 = 4/6 - 3/6=
1/6
3 0
3 years ago
Read 2 more answers
Se tiene la sucesión 3, 8, 13, 18, 23 … ¿Cuáles son los siguientes dos términos y cuál es la regla general?
V125BC [204]

Respuesta:

28; 33

A (n) = 5n - 2

Explicación paso a paso:

A partir de los datos dados, 3, 8, 13, 18, 23…, podemos ver que cada valor sucesivo de la serie aumenta en 5;

Por lo tanto, los siguientes dos términos de la serie deberían ser:

23 + 5 = 28

28 + 5 = 33

La serie es una progresión aritmética:

Recuerde la fórmula general:

A (norte) = a + (norte - 1) d

Donde, a = Primer término = 3; d = diferencia común = 5

n = enésimo término

A (n) = 3 + (n-1) 5

A (n) = 3 + 5n - 5

A (n) = 5n - 2

6 0
3 years ago
What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative. 

---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

4 0
3 years ago
Hru im in an amazing mood help meeeeeeeeeeeee plzzzzzzzzzzzz
strojnjashka [21]

Answer:

I think its A

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?
Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

<u><em>Explanation</em></u>

PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.

According to the graph, the coordinates of P is (-7, -2) and  Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: (\frac{x+2}{2},\frac{y+4}{2}) , which is actually at (-7, -2)

Thus.....

\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0
2 years ago
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