there are 4 tens in a deck so probability of picking a ten is 4/52 reduced to 1/13
there are 13 clubs in a deck, probability for that is 13/52 reduced to 1/4
probability for both is 1/13 x 1/4 = 1/52
So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!
now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?
we have to divide:
35/5=7
so we would use 7 coins.
And the difference is 5: 7-2 is 5.
5b-2=13 add 2 to both sides
5b=15 divide both sides by 5
b=3
C. He forgot to place a zero in the quotient.
see attachment:
Hello!
The solution is where the lines intersect. As you can see, they only intersect at one point.
A) It as one solution.
To find our solution, we just see what the point is they intersect at.As you can see, they intersect at (4,4).
B) (4,4)
I hope this helps!
