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AlladinOne [14]
3 years ago
13

Christie's Auction sold a painting for

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
24,500$. 100%
X$. 15%
X=24,000•15/100
X=3,675 premium

24,000-3,675=20,825$ bidder pay Christine.

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Select the two values of x that are roots of this equation.<br> 2x2 + 11x+15= 0
USPshnik [31]

Answer:

The two values of x are -2.5 and -3

Step-by-step explanation:

we have

2x^{2}+11x+15=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1} {4}=-2.5

x_2=\frac{-11(-)1} {4}=-3

therefore

The two values of x are -2.5 and -3

6 0
3 years ago
Read 2 more answers
How can you find the Mean Absolute Deviation (MAD) for this set of data?
den301095 [7]

Answer: Add all the absolute deviations and divide by number of swimmers.


Step-by-step explanation:

To find the mean absolute deviation of any data we need to follow the following steps:

  • Start by finding the mean of the data set.
  • Find the absolute value of the difference between each data value and the mean.
  • Find the sum of the absolute values of the differences.
  • Divide the sum of the absolute values of the differences by the number of data values.

We can see in the picture that it already dome with first two steps so the step after that is " Add all the absolute deviations and divide by number of swimmers."


5 0
3 years ago
Read 2 more answers
Consider the surface given by
Mazyrski [523]
This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4 
    2x^2 + 5y^2 = 1.75
    Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
    5y^2 + z^2 = 2
    Now you have an ellipse in the x=1 plane as your trace.


(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
    2x^2 + 5y^2 = 4
    Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
    2x^2 + z^2 = 4
    Now you have an ellipse in the y=0 plane as your trace.


5 0
4 years ago
Which of the following statements are not proportional?
Lelechka [254]

Answer:

4/6 = 9/12 is not proportional

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Plz get all correct for branniest
lara31 [8.8K]

Answer:

I just answered it on your other question but

4. AB+BC=AC

6. AC=BD

Step-by-step explanation:

3 0
3 years ago
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