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astra-53 [7]
2 years ago
6

Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain

. How many half-lives transpired during this time period? half-lives Answer = Blank 1:​
Mathematics
2 answers:
iVinArrow [24]2 years ago
5 0

Answer:

2.5 half-lives

Step-by-step explanation:

Find t_{h} in N(t)=N_{0}e^{-kt} given N(t) = 2, N_{0} =64,t=\frac{25}{2}

N(t) is the amount after the time t, N_0 `is the initial amount, t_{h} is the half-life

We know that after half-life there will be twice less the initial quantity:

N(t_{h})=\frac{N_{0} }{2}=N_{0}e^{kt_{h} }.

Simplifying gives \frac{1}{2} =e^{-kt_h} or k = -\frac{In(\frac{1}{2}) }{t_{h} }  .

Plugging this into the initial equation, we obtain that N(t)=N_{0}e^\frac{In(\frac{1}{2}) }{t_{h} }or N(t)= N_{0} (\frac{1}{2})^\frac{t}{t_h}.

Finally, just plug in the given values and find the unknown one.

From 2=64(\frac{1}{2})^\frac{\frac{25}{2} }{t_h}, we have that t_h = \frac{25 In (2)}{2 In (32)\\}

So you should get: t_{h} =\frac{25 In (2)}{2 In (32)\\}=2.5.

<h2><u>MARK ME AS BRAINLIEST IF YOU WISH</u></h2><h2><u /></h2>
son4ous [18]2 years ago
5 0

Answer:

You should def give them brainiest :)

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oksano4ka [1.4K]
That  one is realy hard
5 0
3 years ago
How many different 7-digit number plates can be made if the first 2 digits are letters and the last 5 digits are numbers, for ex
saw5 [17]

Answer:

We can use seven letters and numbers.

I am assuming that any numeral in the range 0..9 or any letter from the English alphabet A..Z can appear in any position, with no blank spaces allowed and no restrictions on repetition. I am also assuming that plates with fewer than seven letters and numbers are not allowed.

So, for example A879BX8 is acceptable, so are 5555555 and ABCDEFG, but not A.123.ZX or…..7A, where the dot represents a space.

I am also assuming that you can only use upper case letters.

With these restrictions, there are 36 possibilities for each space and the total number of valid number plates would be 36^7 = 78,364,164,096, let's say about 78 billion.

It is estimated that there are about 1.3 billion cars, trucks and buses in the road today. This number plate system therefore allows more than enough unique license plates. I'd even hazard a guess that it might be more than enough for every road vehicle that has ever been built or ever will be.

In practice there would be other restrictions, for example only letters in some positions and only numbers in others. There'd still be plenty to go around.

Step-by-step explanation:

5 0
3 years ago
A family goes grocery shopping every week. in a month the costs of the groceries are $72.42, $91.50, $58.99, and $69.02. 5. what
frozen [14]
1) Mean
The mean is given by the sum of the data divided by the number of data (4, in this case):
\mu =   \frac{1}{N} \sum x_i = \frac{1}{4}(72.42+91.50+58.99+69.02) = \frac{291.93}{4}=72.98 $

2) Standard deviation
The standard deviation is given by:
\sigma =  \sqrt{ \frac{1}{N} \sum (x_i-\mu)^2 }
where \mu is the mean, that we already found at point 1), and N=4. Substituting data, we have:
\sigma =  \sqrt{ \frac{1}{4} ((-0.56)^2+(18.52)^2+(-13.99)^2+(-3.96)^2) } =
= \sqrt{ \frac{1}{4}  (554.71)} = \sqrt{138.68} =11.78 $
3 0
3 years ago
Can anyone help ill give more points
Anna11 [10]

Answer:

I don't understand what the question is asking please expain

7 0
3 years ago
The Temperature started out at 92C in the morning and went down to -13C at noon. It stayed at that temparature for six hours and
ioda

the tempayure was at six because it was at 92c and went down to -13c then rose 7c so that means it was at 6 by 6 a.m.

7 0
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