Ask question

Ask question

All categories

3 years ago

14

There are 49 dogs signed up to compete in the dog show. There are 36 more small dogs than large dogs signed up to compete. How m

any small dogs are signed up to compete?

1 answer:

pickupchik [31]3 years ago

6 0

Answer:

Small=36

Large=13

Step-by-step explanation:

As given there are 49 dogs signed up

36 are small so the equation is

36+x=49

x=49-36

x=13

So 13 large dogs and 36 small dogs

You might be interested in

Helpppppppppppppppppppppp

Setler79 [48]

Answer:

EF=3.6

Step-by-step explanation:

I'm going to use Pythagorean Theorem for side EF.

4.8^2+EF^2=6^2

23.04+EF^2=36

-23.04 -23.04

EF^2=12.96

sqrt sqrt

EF=3.6

4 0

3 years ago

For parallelogram LMNO , if m

natali 33 [55]

I'm just going to assume you're given the volume and LMNO are sides of the parallelogram

Area = LMNO

M=?

M= $\frac{area}{LNO}$

5 0

3 years ago

Please help this is timed

max2010maxim [7]

Answer:

The last one (f) hope u still have time

7 0

3 years ago

a recent survey shows that 16% of college students have dogs and 38% have an HBO subscription. assuming these two events are ind

Nataly_w [17]

Answer: $0.939\ or\ 93.9\%$

Step-by-step explanation:

Given

Survey shows that 16% of college students have dogs and 38% have HBO subscription

Probability that a random person have both is

$\Rightarrow P_o=0.16\times 0.38\quad [\text{As both events are independent}]\\\Rightarrow P_o=0.0608$

The probability that the random person has neither of the two is

$\Rightarrow P=1-P_o\\\Rightarrow P=1-0.0608\\\Rightarrow P=0.939$

3 0

3 years ago

Plssss helppp meeeee

saw5 [17]

Answer:

the answer should be 152.6 ! just moving the decimal over to the left!!

8 0

2 years ago