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solniwko [45]
3 years ago
14

If

{1845} " align="absmiddle" class="latex-formula">
then find the value​
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

\qquad\bullet\quad {:}\dashrightarrow\rm \sqrt [2]{1845}}

\qquad\bullet\quad {:}\dashrightarrow\rm\sqrt [2]{1845}

\qquad\bullet\quad {:}\dashrightarrow\rm sqrt[345]{2096}

<h3><u>Learn</u><u> </u><u>more</u><u>:</u><u>-</u></h3>

fraction rules

\boxed{\begin{minipage}{6 cm}\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{B} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}\end{minipage}}

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MariettaO [177]

Answer:

\angle 2 =60

\angle 3 = 60

\angle 4 = 120

\angle 5 = 120

\angle 6 = 60

\angle 7 = 60

\angle 8 = 120

Step-by-step explanation:

Given

\angle 1 = 120^\circ

See attachment

Required

Determine the other angles

\angle 1 and \angle 2 are on a straight line.

So;

\angle 1 + \angle 2 =180

Make \angle 2 the subject

\angle 2 =180 - \angle 1

\angle 2 =180 - 120

\angle 2 =60

\angle 1 , \angle 4,  \angle 5 and \angle 8 are corresponding angles.

So;

\angle 4 =\angle 1 = 120

\angle 5 =\angle 1 = 120

\angle 8 =\angle 1 = 120

Similarly; \angle 2 , \angle 3,  \angle 6 and \angle 7 are corresponding angles.

So;

\angle 3 =\angle 2 = 60

\angle 6 =\angle 2 = 60

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ipn [44]
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6 0
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What is the median in this set of data?<br> 14, 19, 26, 28, 18, 21, 30, 27
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Step-by-step explanation:

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3 0
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Lady bird [3.3K]

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You bought a bag of tamales and one of your friends ate 1/5 of the entire bag and another friend ate 1/3 of the whole bag. How m
Serggg [28]

Answer:

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Step-by-step explanation:

So, you need to find a common denominator between 3 and 5 which is 15

multiply the numerator and the denominator by 3 in 1/5. Then, multiply the numerator and the denominator by 5 in 1/3.

1/3*5=5/15

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Add them together.

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Lastly, subtract 15/15 by 8/15

15/15-8/15=7/15

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