Answer:
11.875
Step-by-step explanation:
2-1, 3-2, 4-3, 1*1, 1/7, any number of expressions fit the bill here.
No, you should have reduced each base to...
3^(3*2x) = 3^(2*(x-3))
and then you can cancel each base
3*2x = 2*(x-3)
6x = 2x-6
4x= -6
x = -3/2
What goes in goes out. This means none of the current is lost. So if 0.7amps+0.68amps+0.47amps = 1.85 amps comes in, then 1.85 amps goes out. So far we have 0.8 amps+0.55 amps going out= 1.35 amps. This means we need an additional 1.85-1.35amps going out= 0.5 amps for the third outgoing current. Cheers!
What is the answer to this fraction division problem? 1/8÷1/16