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3 years ago

Can someone explain this to me pweaseee

Mathematics

1 answer:

lions [1.4K]3 years ago

3 0

Answer:

D. 181.7 miles

Step-by-step explanation:

If the odometer can read to the nearest 0.1 miles, then you don't want to use A because its not as precise. You don't want to use B because its rounded up to the nearest hundreds. You don't want to use C because we don't know whats in the hundredths place, if the odometer only reads to the nearest 0.1 miles then it could be 181.3, or 181.9, we don't know that. Your answer is D.

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Their sum is 6 and their difference is 36 Help plz

Ivan

Answer:

Step-by-step explanation:

if you can use negative numbers then you could use 21 and -15

adding them together is 21 + (-15) = 6

and then subtracting 21 - (-15) =

21 + 15 = 36

do you think that would work ? :/

3 0

3 years ago

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If there is a class of 30 students and 6 of them are off, what fraction of students are there and what percentage of students ar

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2 years ago

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$