Well you are given the equation so let's plug in for kaylib and see how many miles she can see
distance = sqrt [(3 * height) / 2]
d = sqrt [(3 *48) / 2]
d = sqrt (144 / 2)
d = sqrt (72)
d = sqrt (3 * 3 * 2 * 2 * 2)
d = 6 * sqrt (2)
You you did not list Addisons height but I will say she is at x feet above sea level. we plug in x for height:
d = sqrt [(3x) / 2]
It it says how much farther for Addison which means she can see farther. to find difference we just subtract kaylibs distance from Addison. so:
sqrt [(3x) / 2] - 6 * sqrt (2)
plug in your x and use a calculator to get a decimal approximation
it is 10...,,,,....,,,,,,,,,,?,,?????
Answer:
y = 5x + 3
Step-by-step explanation:
The answer that belongs in the ? is 5.
Answer:
The Answer is B.
Step-by-step explanation:
I got it right on my test
For further evidence here is a picture of the answer
Answer:
Tan E = 2 / 7.75
Sin G = 7.75 / 8
Sec G = 4
Step-by-step explanation:
Find the attached document for better illustration of the triangle
Assuming the hypothenus of the triangle is 8 = EG since it's the longest side of the triangle.
FG = 2 = opposite side of the triangle.
We can use pythagorean theorem to find the adjacent of the triangle since we already know two sides.
EG² = FG² + EF²
EF² = EG² - FG²
EF² = 8² - 2²
EF² = 64 - 4
EF² = 60
EF = √(60)
EF = 7.7459 = 7.75
To find the respective trignometric ratio, we can use the relation SOH CAH TOA
Sine = opposite / hypothenus
Cosine = adjacent/ hypothenus
Tangent = opposite/ adjacent
A. tan E
Tan E = opposite/ adjacent
Tan E = 2 / 7.75
Tan E = 0.2580
B. Sin G = opposite / hypothenus
Sin G = 7.75 / 8
Sin G = 0.9687
C. Sec G = 1 / cos G
Cos G = adjacent / hypothenus
Sec G = 1 / (adjacent / hypothenus)
Sec G = hypothenus/ adjacent
Sec G = 8 / 2
Sec G = 4