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Triss [41]
3 years ago
11

Can y’all answer the middle one Ill mark you brainlist.

Mathematics
2 answers:
MissTica3 years ago
5 0

If you are asking and need to round it up it will come up to

4.444

You need to round it up because the 4.444 goes on and on infinitely.

If you needed another answer comment what it is you need and I will answer you on there.

YW

777dan777 [17]3 years ago
3 0

Answer:

4.44 infinet

Step-by-step explanation:

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3 1/4 divided by 2 2/3 <br> (convert to mixed number)
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Answer:

3 1/8

Step-by-step explanation:

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How many 4 card hands that contain exactly 3 aces and 1 queen can be chosen from a 52 card deck?
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Choosing 3 aces from 4 possible is expressed by:
_4C_3=\frac{4!}{3!1!} = 4

Choosing 1 queen from 4 possible is expressed by:
_4C_1=\frac{4!}{1!3!}=4

This gives us 4*4 = 16 possible hands.
7 0
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Maksim231197 [3]

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Step-by-step explanation:

8 0
3 years ago
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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random
Katen [24]

Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

x_2 = 54 --- City K

Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

7 0
2 years ago
Which relationship describes angles 1 and 2?
galina1969 [7]
Angle 1 and 2 are vertical angles

Hope this helps :)
8 0
3 years ago
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