Answer:
72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
A study indicates that 62% of students have have a laptop.
This means that 
You randomly sample 8 students.
This means that 
Find the probability that between 4 and 6 (including endpoints) have a laptop.






72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Answer:
180%
Step-by-step explanation:
Set up an equation:
Variable x = percent of markup
102.56/56.98 = x/100
Cross multiply
102.56 × 100 = 56.98 × x
10,256 = 56.98x
Divide both sides by 56.98:
179.99297.... = x
Round to nearest whole number:
180 = x
Check your work:
56.98 × 180%
Convert the percentage into a decimal:
56.98 × 1.80
102.564
Round to nearest cent:
102.56
Correct!
Given Information:
Mean SAT score = μ = 1500
Standard deviation of SAT score = σ = 3
00
Required Information:
Minimum score in the top 10% of this test that qualifies for the scholarship = ?
Answer:

Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

Therefore, you need to score 1884 in order to qualify for the scholarship.
How to use z-table?
Step 1:
In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2
Step 2:
Then look up at the top of z-table and note down the value of the that column which is 0.08
Step 3:
Finally, note down the intersection of step 1 and step 2 which is 1.28